/**
 * Sample solution to Gallup
 * Uses only integer arithmatic.
 * Author: Mikael Goldmann
 */

import java.util.*;
import java.io.*;

class Gallup
{

    static final int MAX = 10000;

    static BufferedReader stdin = 
	new BufferedReader(new InputStreamReader(System.in));
    static PrintWriter stdout = 
	new PrintWriter(
			new BufferedWriter(new OutputStreamWriter(System.out)));
    public static void main(String args[]) 
    {
	int cnt = 0;
	try { while( solve(++cnt) ); }
	catch (Exception e) { /* skip */}
	stdout.close();
    }
    
    static boolean solve(int cnt) throws Exception
    {
	String s="";
	int i;
	StringTokenizer st = new StringTokenizer(stdin.readLine());	
	int             np = Integer.parseInt(st.nextToken());
	double[]         p = new double[np];
	long[]           a = new long[np];
	if (np == 0) return false;

	stdout.print("Case " + cnt + ": ");
	for (i = 0; i < np; ++i) {
	    s = st.nextToken();
	    p[i] = Double.parseDouble(s);
	}
	
	i = s.indexOf('.');
	int ndec = 0;
	if (i != -1) ndec = s.length()-i-1;
	
	long exp_10_d = 1;
	for (i = 0; i < ndec; ++i) exp_10_d *= 10;
	
	for (i = 0; i < np; ++i) a[i] = (long)(exp_10_d * p[i] + 0.1);

	long minpeople;
	long lo,hi;
	long losum, hisum;
	boolean ok = true;
	for (minpeople = 1; minpeople < MAX; ++minpeople) {
	    losum = hisum = 0;
	    ok = true;
	    for (i = 0; ok && i < np; ++i) {
		lo = ((2*a[i]-1)*minpeople)/(2*100*exp_10_d);
		hi = 1+((2*a[i]+1)*minpeople)/(2*100*exp_10_d);
		while (2*100*exp_10_d*lo <  minpeople*(2*a[i]-1)) ++lo;
		while (2*100*exp_10_d*hi >= minpeople*(2*a[i]+1)) --hi;
		ok = (lo <= hi);
		losum += lo;
		hisum += hi;
	    }
	    if (ok && losum <= minpeople && hisum >= minpeople) break;
	}
	if (ok && minpeople < MAX)
	    stdout.println(minpeople);
	else 
	    stdout.println("error");
	return true;
    }
}